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1
GATE Electrical 2016 Set 1 | Question: 31
Consider the following state-space representation of a linear time-invariant system. $x(t)=\begin{pmatrix} 1&0 \\ 0&2 \end{pmatrix} x(t), y(t)= c^{T} x(t), c =\begin{pmatrix} 1& \\ 1& \end{pmatrix} \text {and } x(0)= \begin{pmatrix} 1& \\ 1& \end{pmatrix}$ The value of $y(t)$ for $t =\log_{e} 2$ is __________.
Consider the following state-space representation of a linear time-invariant system.$x(t)=\begin{pmatrix}1&0 \\0&2\end{pmatrix}x(t), y(t)= c^{T} x(t), c =\begin{pmatrix}1...
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1.9k
points
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edited
Oct 3, 2020
Control Systems
gate2016-ee-1
transformation
state-space-equations
correlation
numerical-answers
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–
0
votes
0
answers
2
GATE Electrical 2016 Set 1 | Question: 32
Loop transfer function of a feedback system is $G(s)H(s)=\dfrac{s+3}{s^{2}(s-3)}$. Take the Nyquist contour in the clockwise direction. Then, the Nyquist plot of $G(s) H (s)$ encircles $-1 + j0$ Once in clockwise direction Twice in clockwise direction Once in anticlockwise direction Twice in anticlockwise direction
Loop transfer function of a feedback system is $G(s)H(s)=\dfrac{s+3}{s^{2}(s-3)}$. Take the Nyquist contour in the clockwise direction. Then, the Nyquist plot of $G(s) H ...
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1.9k
points
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edited
Oct 3, 2020
Control Systems
gate2016-ee-1
closed-loop-system
nyquist-stability
mapping
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0
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0
answers
3
GATE Electrical 2016 Set 1 | Question: 30
Consider the following asymptotic Bode magnitude plot ($\omega$ is in rad/s). Which one of the following transfer functions is best represented by the above Bode magnitude plot? $\dfrac{2s}{(1+0.5s)(1+0.25s)^{2}} \\$ $\dfrac{4(1+0.5s)}{s(1+0.25s)} \\$ $\dfrac{2s}{(1+2s)(1+4s)} \\$ $\dfrac{4s}{(1+2s)(1+4s)^{2}}$
Consider the following asymptotic Bode magnitude plot ($\omega$ is in rad/s).Which one of the following transfer functions is best represented by the above Bode magnitude...
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1.9k
points
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edited
Oct 3, 2020
Control Systems
gate2016-ee-1
logarithmic-plot
gain-k
integral-and-derivative-factor
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0
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0
answers
4
GATE Electrical 2016 Set 1 | Question: 7
The phase cross-over frequency of the transfer function $G(s)=\dfrac{100}{(s+1)^{3}}$ in rad/s is $\sqrt{3} \\$ $\dfrac{1}{\sqrt{3}} \\$ $3 \\$ $3\sqrt{3}$
The phase cross-over frequency of the transfer function $G(s)=\dfrac{100}{(s+1)^{3}}$ in rad/s is$\sqrt{3} \\$$\dfrac{1}{\sqrt{3}} \\$$3 \\$$3\sqrt{3}$
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1.9k
points
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edited
Oct 3, 2020
Control Systems
gate2016-ee-1
mathematical-representation
cross-over-frequency
180-phase-shift
bode-stability-criteria
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0
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0
answers
5
GATE Electrical 2016 Set 1 | Question: 6
The transfer function of a system is $\dfrac{Y(s)}{R(s)}=\dfrac{s}{s+2}$. The steady state output $y(t)$ is $A \cos (2t + \phi)$ for the input $\cos (2t)$. The values of $A$ and $\phi$ respectively are $\dfrac{1}{\sqrt{2}}, -45^\circ$ $\dfrac{1}{\sqrt{2}}, +45^\circ$ $\sqrt{2}, -45^\circ$ $\sqrt{2}, +45^\circ$
The transfer function of a system is $\dfrac{Y(s)}{R(s)}=\dfrac{s}{s+2}$. The steady state output $y(t)$ is $A \cos (2t + \phi)$ for the input $\cos (2t)$. The values of ...
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1.9k
points
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edited
Oct 3, 2020
Control Systems
gate2016-ee-1
laplace-transform
convolution-integral
feed-back-transfer-function
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0
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0
answers
6
GATE Electrical 2015 Set 2 | Question: 11
The operational amplifier shown in the figure is ideal. The input voltage (in Volt) is $V_{i} = 2 \sin(2\pi \times 2000t)$. The amplitude of the output voltage $V_{o}$ (in Volt) is ________.
The operational amplifier shown in the figure is ideal. The input voltage (in Volt) is $V_{i} = 2 \sin(2\pi \times 2000t)$. The amplitude of the output voltage $V_{o}$ (i...
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1.9k
points
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edited
Oct 2, 2020
Control Systems
gate2015-ee-2
operational-amplifier
pid-controller
numerical-answers
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0
votes
0
answers
7
GATE Electrical 2014 Set 3 | Question: 17
The signal flow graph of a system is shown below. $U(s)$ is the input and $C(s)$ is the output. Assuming, $h_1=b_1$ and $h_0=b_0-b_1a_1$ , the input-output transfer function, $G(s)=\dfrac{C(s)}{U(s)}$ ... $G(s)=\dfrac{b_1s+b_0}{s^2+a_1s+a_0} \\$ $G(s)=\dfrac{a_0s+a1}{s^2+b_0s+b_1}$
The signal flow graph of a system is shown below. $U(s)$ is the input and $C(s)$ is the output.Assuming, $h_1=b_1$ and $h_0=b_0-b_1a_1$ , the input-output transfer functi...
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1.9k
points
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edited
Oct 1, 2020
Control Systems
gate2014-ee-3
stability
bode-plot
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0
votes
0
answers
8
GATE Electrical 2015 Set 1 | Question: 39
The op-amp shown in the figure has a finite gain $A = 1000$ and an infinite input resistance. A step-voltage $V_{i} = 1 \: mV$ is applied at the input at time $t = 0$ as shown. Assuming that the operational amplifier is not saturated, the time constant (in millisecond) of the output voltage $V_{o}$ is $1001$ $101$ $11$ $1$
The op-amp shown in the figure has a finite gain $A = 1000$ and an infinite input resistance. A step-voltage $V_{i} = 1 \: mV$ is applied at the input at time $t = 0$ as ...
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1.9k
points
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edited
Sep 25, 2020
Control Systems
gate2015-ee-1
time-constant
operational-amplifier
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–
0
votes
0
answers
9
GATE Electrical 2015 Set 1 | Question: 25
For the signal-flow graph shown in the figure, which one of the following expressions is equal to the transfer function $\dfrac{Y(s)}{X_{2}(s)}\bigg \vert _{X_{1}(s)=0}$ ? $\dfrac{G_{1}}{1+G_{2}(1+G_{1})} \\$ $\dfrac{G_{2}}{1+G_{1}(1+G_{2})} \\$ $\dfrac{G_{1}}{1+G_{1}G_{2}} \\$ $\dfrac{G_{2}}{1+G_{1}G_{2}}$
For the signal-flow graph shown in the figure, which one of the following expressions is equal to the transfer function $\dfrac{Y(s)}{X_{2}(s)}\bigg \vert _{X_{1}(s)=0}$ ...
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1.9k
points
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edited
Sep 25, 2020
Control Systems
gate2015-ee-1
signal-flow-graph
transfer-function
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0
votes
0
answers
10
GATE Electrical 2015 Set 1 | Question: 24
A Bode magnitude plot for the transfer function $G(s)$ of a plant is shown in the figure. Which one of the following transfer functions best describes the plant? $\dfrac{1000(s+10)}{s+1000} \\$ $\dfrac{10(s+10)}{s(s+1000)} \\$ $\dfrac{s+1000}{10s(s+10)} \\$ $\dfrac{s+1000}{10(s+10)}$
A Bode magnitude plot for the transfer function $G(s)$ of a plant is shown in the figure. Which one of the following transfer functions best describes the plant?$\dfrac{1...
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1.9k
points
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edited
Sep 25, 2020
Control Systems
gate2015-ee-1
bode-plot
stability
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–
0
votes
0
answers
11
GATE Electrical 2015 Set 1 | Question: 13
Consider the circuit shown in the figure. In this circuit $R=1 k\Omega$, and $C=1 \mu F$. The input voltage is sinusoidal with a frequency of $50$ Hz, represented as a phasor with magnitude $V_{i}$ and phase angle $0$ radian as shown in the figure. The output ... to the phase angle of the input voltage? $0 \\$ $\pi \\$ $\dfrac{\pi}{2} \\$ $-\dfrac{\pi}{2}$
Consider the circuit shown in the figure. In this circuit $R=1 k\Omega$, and $C=1 \mu F$. The input voltage is sinusoidal with a frequency of $50$ Hz, represented as a ph...
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1.9k
points
go_editor
edited
Sep 25, 2020
Control Systems
gate2015-ee-1
operational-amplifier
feedback-system
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–
0
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0
answers
12
GATE Electrical 2015 Set 1 | Question: 10
The impulse response $g(t)$ of a system, $G$, is as shown in Figure $(a)$. What is the maximum value attained by the impulse response of two cascaded blocks of $G$ as shown in Figure $(b)$? $\dfrac{2}{3} \\$ $\dfrac{3}{4} \\$ $\dfrac{4}{5} \\$ $1$
The impulse response $g(t)$ of a system, $G$, is as shown in Figure $(a)$. What is the maximum value attained by the impulse response of two cascaded blocks of $G$ as sho...
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1.9k
points
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edited
Sep 25, 2020
Control Systems
gate2015-ee-1
impulse-response
cascaded-blocks
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–
0
votes
0
answers
13
GATE Electrical 2014 Set 3 | Question: 44
The block diagram of a system is shown in the figure If the desired transfer function of the system is $\dfrac{C(s)}{R(s)}=\dfrac{s}{s^2+s+1}$ then $G(s)$ is $1$ $s$ $1/s$ $\dfrac{-s}{s^3+s^2-s-2}$
The block diagram of a system is shown in the figureIf the desired transfer function of the system is $\dfrac{C(s)}{R(s)}=\dfrac{s}{s^2+s+1}$ then $G(s)$ is$1$$s$$1/s$$\d...
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1.9k
points
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edited
Sep 24, 2020
Control Systems
gate2014-ee-3
feedback
closed-loop-system
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–
0
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0
answers
14
GATE Electrical 2014 Set 2 | Question: 46
The second order dynamic system $\dfrac{dX}{dt}=PX+Qu$ $y=RX$ has the matrices $P$, $Q$ and $R$ as follows: $P=\begin{bmatrix} -1 & 1\\ 0& -3 \end{bmatrix}$ ... the following controllability and observability properties: Controllable and observable Not controllable but observable Controllable but not observable Not controllable and not observable
The second order dynamic system$\dfrac{dX}{dt}=PX+Qu$$y=RX$has the matrices $P$, $Q$ and $R$ as follows:$P=\begin{bmatrix} -1 & 1\\ 0& -3 \end{bmatrix}$ $Q=\begin{bmatri...
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1.9k
points
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edited
Sep 24, 2020
Control Systems
gate2014-ee-2
dynamic-system
controlability
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–
0
votes
0
answers
15
GATE Electrical 2014 Set 2 | Question: 45
For the transfer function $G(s)=\dfrac{5(s+2)}{s(s+0.25)(s^2+4s+25)}$ The values of the constant gain term and the highest corner frequency of the Bode plot respectively are $3.2$ , $5.0$ $16.0$ , $4.0$ $3.2$ , $4.0$ $16.0$ , $5.0$
For the transfer function $$G(s)=\dfrac{5(s+2)}{s(s+0.25)(s^2+4s+25)}$$ The values of the constant gain term and the highest corner frequency of the Bode plot respectivel...
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1.9k
points
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edited
Sep 24, 2020
Control Systems
gate2014-ee-2
transfer-function
gain
bode-plot
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–
0
votes
0
answers
16
GATE Electrical 2014 Set 2 | Question: 44
A system with the open loop transfer function $G(s)=\dfrac{K}{s(s+2)(s^2+2s+2)}$ is connected in a negative feedback configuration with a feedback gain of unity. For the closed loop system to be marginally stable, the value of $K$ is ______
A system with the open loop transfer function $$G(s)=\dfrac{K}{s(s+2)(s^2+2s+2)}$$ is connected in a negative feedback configuration with a feedback gain of unity. For th...
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1.9k
points
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edited
Sep 24, 2020
Control Systems
gate2014-ee-2
negative-feedback
marginally-stable
numerical-answers
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–
0
votes
0
answers
17
GATE Electrical 2014 Set 2 | Question: 17
The closed loop transfer function of a system is $T(s)=\dfrac{4}{s^2+0.4S+4}$ The steady state error due to unit step input is __________.
The closed loop transfer function of a system is $T(s)=\dfrac{4}{s^2+0.4S+4}$ The steady state error due to unit step input is __________.
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1.9k
points
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edited
Sep 24, 2020
Control Systems
gate2014-ee-2
unit-step-function
closed-loop-system
numerical-answers
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–
0
votes
0
answers
18
GATE Electrical 2014 Set 2 | Question: 9
Consider an LTI system with transfer function $H(s)=\frac{1}{s(s+4)}$ If the input to the system is $ \cos(3t)$ and the steady state output is $A \sin(3t+\alpha )$ , then the value of $A$ is $1/30$ $1/15$ $3/4$ $4/3$
Consider an LTI system with transfer function $$H(s)=\frac{1}{s(s+4)}$$ If the input to the system is $ \cos(3t)$ and the steady state output is $A \sin(3t+\alpha )$ , th...
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1.9k
points
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edited
Sep 24, 2020
Control Systems
gate2014-ee-2
linear-time-invariant-system
transfer-function
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0
votes
0
answers
19
GATE Electrical 2014 Set 1 | Question: 51
In the figure shown, assume the op-amp to be ideal. Which of the alternatives gives the correct Bode plots for the transfer function $\dfrac{V_o(\omega )}{V_i(\omega )}?$
In the figure shown, assume the op-amp to be ideal. Which of the alternatives gives the correct Bode plots for the transfer function $\dfrac{V_o(\omega )}{V_i(\omega )}?$...
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1.9k
points
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edited
Sep 24, 2020
Control Systems
gate2014-ee-1
transfer
function
operational-amplifier
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–
0
votes
0
answers
20
GATE Electrical 2014 Set 1 | Question: 18
The root locus of a unity feedback system is shown in the figure The closed loop transfer function of the system is $\dfrac{C(s)}{R(s)}=\dfrac{K}{(s+1)(s+2)} \\$ $\dfrac{C(s)}{R(s)}=\dfrac{-K}{(s+1)(s+2)+K} \\$ $\dfrac{C(s)}{R(s)}=\dfrac{K}{(s+1)(s+2)-K} \\$ $\dfrac{C(s)}{R(s)}=\dfrac{K}{(s+1)(s+2)+K}$
The root locus of a unity feedback system is shown in the figureThe closed loop transfer function of the system is$\dfrac{C(s)}{R(s)}=\dfrac{K}{(s+1)(s+2)} \\$$\dfrac{C(s...
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1.9k
points
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edited
Sep 24, 2020
Control Systems
gate2014-ee-1
stability
bode-plot
+
–
0
votes
0
answers
21
GATE Electrical 2013 | Question: 40
The signal flow graph for a system is given below. The transfer function $\dfrac{Y(s)}{U(s)}$ for this system is $\dfrac{s+1}{5s^2+6s+2} \\$ $\dfrac{s+1}{s^2+6s+2} \\$ $\dfrac{s+1}{s^2+4s+2} \\$ $\dfrac{1}{5s^2+6s+2}$
The signal flow graph for a system is given below. The transfer function $\dfrac{Y(s)}{U(s)}$ for this system is$\dfrac{s+1}{5s^2+6s+2} \\$$\dfrac{s+1}{s^2+6s+2} \\$$\d...
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1.9k
points
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edited
Sep 23, 2020
Control Systems
gate2013-ee
controllers
stability
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–
0
votes
0
answers
22
GATE Electrical 2013 | Question: 15
The Bode plot of a transfer function $G(s)$ is shown in the figure below. The gain $\big(20 \log\mid G(s) \mid \big)$ is $32 dB$ and $-8 dB$ at $1$ rad/s and $10$ rad/s respectively. The phase is negative for all $\omega$. Then $G(s)$ is $\dfrac{39.8}{s} \\$ $\dfrac{39.8}{s^2} \\$ $\dfrac{32}{s} \\$ $\dfrac{32}{s^2}$
The Bode plot of a transfer function $G(s)$ is shown in the figure below.The gain $\big(20 \log\mid G(s) \mid \big)$ is $32 dB$ and $-8 dB$ at $1$ rad/s and $10$ rad/s r...
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1.9k
points
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edited
Sep 23, 2020
Control Systems
gate2013-ee
gain
stability
+
–
0
votes
0
answers
23
GATE Electrical 2013 | Question: 2
The transfer function $\dfrac{V2(s)}{V1(s)}$ of the circuit shown below is $\dfrac{0.5s+1}{s+1} \\$ $\dfrac{3s+6}{s+2} \\$ $\dfrac{s+2}{s+1} \\$ $\dfrac{s+1}{s+2}$
The transfer function $\dfrac{V2(s)}{V1(s)}$ of the circuit shown below is$\dfrac{0.5s+1}{s+1} \\$$\dfrac{3s+6}{s+2} \\$$\dfrac{s+2}{s+1} \\$$\dfrac{s+1}{s+2}$
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1.9k
points
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edited
Sep 23, 2020
Control Systems
gate2013-ee
block-diagram
voltage-source
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–
0
votes
0
answers
24
GATE Electrical 2013 | Question: 3
Assuming zero initial condition, the response $y(t)$ of the system given below to a unit step input $u(t)$ is? $u(t) \\$ $t\:u(t) \\$ $\dfrac{t^2}{2}u(t) \\$ $e^{-t}u(t)$
Assuming zero initial condition, the response $y(t)$ of the system given below to a unit step input $u(t)$ is? $u(t) \\$$t\:u(t) \\$$\dfrac{t^2}{2}u(t) \\$$e^{-t}u(t)$
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1.9k
points
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edited
Sep 23, 2020
Control Systems
gate2013-ee
impulse-response
step-function
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–
0
votes
0
answers
25
GATE Electrical 2015 Set 2 | Question: 24
An open loop control system results in a response of $e^{-2t}(\sin 5t+\cos 5t)$ for a unit impulse input. The $DC$ gain of the control system is ________.
An open loop control system results in a response of $e^{-2t}(\sin 5t+\cos 5t)$ for a unit impulse input. The $DC$ gain of the control system is ________.
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1.9k
points
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retagged
Dec 4, 2019
Control Systems
gate2015-ee-2
open-loop-system
independant-system
numerical-answers
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–
0
votes
0
answers
26
GATE Electrical 2014 Set 1 | Question: 44
For the given system, it is desired that the system be stable. The minimum value of $\alpha$ for this condition is ____________. .
For the given system, it is desired that the system be stable. The minimum value of $\alpha$ for this condition is ____________..
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1.9k
points
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retagged
Dec 2, 2019
Control Systems
gate2014-ee-1
feed-back-system
stability
numerical-answers
+
–
0
votes
0
answers
27
GATE Electrical 2014 Set 3 | Question: 46
The magnitude Bode plot of a network is shown in the figure The maximum phase angle $\phi _m$ and the corresponding gain $G_m$ respectively, are $-30^{\circ}$ and $1.73$ $dB$ $-30^{\circ}$ and $477$ $dB$ $+30^{\circ}$ and $4.77$ $dB$ $+30^{\circ}$ and $1.73$ $dB$
The magnitude Bode plot of a network is shown in the figureThe maximum phase angle $\phi _m$ and the corresponding gain $G_m$ respectively, are$-30^{\circ}$ and $1.73$ $d...
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1.9k
points
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edited
Nov 21, 2019
Control Systems
gate2014-ee-3
bode-plot
stability
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–
0
votes
0
answers
28
GATE Electrical 2013 | Question: 5
Which of the following statement is NOT TRUE for a continuous time causal and stable $LTI$ system? All the poles of the system must lie on the left side of $j\omega$ axis Zeros of the system can lie anywhere in the $s$ - plane All the poles ... within $\mid s\mid=1$ All the roots of the characteristic equation must be located on the left side of $j\omega$ axis
Which of the following statement is NOT TRUE for a continuous time causal and stable $LTI$ system?All the poles of the system must lie on the left side of $j\omega$ axisZ...
Lakshman Bhaiya
6.7k
points
Lakshman Bhaiya
edited
Nov 20, 2019
Control Systems
gate2013-ee
stability
block-diagram
+
–
0
votes
0
answers
29
GATE Electrical 2013 | Question: 13
In the feedback network shown below,if the feedback factor $k$ is increased, then the input impedance increases and output impedance decreases. input impedance increases and output impedance also increases. input impedance decreases and output impedance also decreases. input impedance decreases and output impedance increases.
In the feedback network shown below,if the feedback factor $k$ is increased, then theinput impedance increases and output impedance decreases.input impedance increases an...
Lakshman Bhaiya
6.7k
points
Lakshman Bhaiya
edited
Nov 20, 2019
Control Systems
gate2013-ee
network-analysis
branches
+
–
0
votes
0
answers
30
GATE Electrical 2013 | Question: 28
The open-loop transfer function of a dc motor is given as $\dfrac{\omega (s)}{V_a(s)}=\dfrac{10}{1+10s}$.When connected in feedback as shown below, the approximate value of $K_a$ that will reduce the time constant of the closed loop system by one hundred times as compared to that of the open-loop system is $1$ $5$ $10$ $100$
The open-loop transfer function of a dc motor is given as $\dfrac{\omega (s)}{V_a(s)}=\dfrac{10}{1+10s}$.When connected in feedback as shown below, the approximate value ...
Lakshman Bhaiya
6.7k
points
Lakshman Bhaiya
edited
Nov 20, 2019
Control Systems
gate2013-ee
feed-back-system
closed-loop-system
+
–
0
votes
0
answers
31
GATE Electrical 2016 Set 2 | Question: 52
The gain at the breakaway point of the root locus of a unity feedback system with open loop transfer function $G(s)=\frac{Ks}{(s-1)(s-4)}$ is $1$ $2$ $5$ $9$
The gain at the breakaway point of the root locus of a unity feedback system with open loop transfer function $G(s)=\frac{Ks}{(s-1)(s-4)}$ is$1$$2$ $5$$9$
piyag476
1.6k
points
piyag476
recategorized
Feb 28, 2017
Control Systems
gate2016-ee-2
gain
breakaway-point
unity-feedback-system
+
–
0
votes
0
answers
32
GATE Electrical 2016 Set 2 | Question: 39
The open loop transfer function of a unity feedback control system is given by $G(s)=\frac{k(s+1)}{s(1+Ts)(1+2S)'}, K > 0, T > 0.$ The closed loop system will be stable if $0 < T < \frac{4(K+1)}{K-1}$ $0 < K < \frac{4(T+2)}{T-2}$ $0 < K < \frac{T+2}{T-2}$ $0 < T < \frac{8(k+1)}{K-1}$
The open loop transfer function of a unity feedback control system is given by$G(s)=\frac{k(s+1)}{s(1+Ts)(1+2S)'}, K 0, T 0.$The closed loop system will be stable if$0 ...
piyag476
1.6k
points
piyag476
recategorized
Feb 28, 2017
Control Systems
gate2016-ee-2
transfer-function
unity-feedback-control-system
+
–
0
votes
0
answers
33
GATE Electrical 2016 Set 2 | Question: 50
A second-order real system has the following properties: a) the damping ratio $\zeta=0.5$ and undamped natural frequency $\omega _{n}=10$ rad/s b) the steady state value of the output, to a unit step input, is $1.02$ ... $\frac{102}{s^{2}+10s+100}$ $\frac{100}{s^{2}+10s+100}$ $\frac{102}{s^{2}+5s+100}$
A second-order real system has the following properties:a) the damping ratio $\zeta=0.5$ and undamped natural frequency $\omega _{n}=10$ rad/sb) the steady state value of...
piyag476
1.6k
points
piyag476
recategorized
Feb 28, 2017
Control Systems
gate2016-ee-2
damping-ratio
natural-frequency
+
–
0
votes
0
answers
34
GATE Electrical 2015 Set 1 | Question: 52
In the signal flow diagram given in the figure, $u_{1}$ and $u_{2}$ are possible inputs whereas $y_{1}$ and $y_{2}$ are possible outputs. When would the SISO system derived from this diagram be controllable and observable? When $u_{1}$ is the only input ... input and $y_{2}$ is the only output. When $u_{2}$ is the only input and $y_{2}$ is the only output.
In the signal flow diagram given in the figure, $u_{1}$ and $u_{2}$ are possible inputs whereas $y_{1}$ and $y_{2}$ are possible outputs. When would the SISO system deriv...
piyag476
1.6k
points
piyag476
recategorized
Feb 28, 2017
Control Systems
gate2015-ee-1
flow-diagram
transfer-function
+
–
0
votes
0
answers
35
GATE Electrical 2015 Set 1 | Question: 53
The transfer function of a second order real system with a perfectly flat magnitude response of unity has a pole at $(2 − j3)$. List all the poles and zeroes. Poles at $(2 \pm j3)$, no zeroes. Poles at $(\pm 2 − j3)$, one zero at origin. Poles at $(2 − j3)$, $(−2 + j3)$, zeroes at $(−2 − j3)$, $(2 + j3)$. Poles at $(2 \pm j3)$, zeroes at $(−2 \pm j3)$.
The transfer function of a second order real system with a perfectly flat magnitude response of unity has a pole at $(2 − j3)$. List all the poles and zeroes.Poles at $...
piyag476
1.6k
points
piyag476
recategorized
Feb 28, 2017
Control Systems
gate2015-ee-1
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poles
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36
GATE Electrical 2015 Set 1 | Question: 55
The open loop poles of a third order unity feedback system are at $0, −1, −2$. Let the frequency corresponding to the point where the root locus of the system transits to unstable region be $K$. Now suppose we introduce a zero in ... a frequency less than $K$ It corresponds to a frequency $K$ Root locus of modified system never transits to unstable region
The open loop poles of a third order unity feedback system are at $0, −1, −2$. Let the frequency corresponding to the point where the root locus of the system transit...
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Control Systems
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37
GATE Electrical 2015 Set 2 | Question: 25
Nyquist plots of two functions $G_{1}(s)$ and $G_{2}(s)$ are shown in figure. Nyquist plot of the product of $G_{1}(s)$ and $G_{2}(s)$ is
Nyquist plots of two functions $G_{1}(s)$ and $G_{2}(s)$ are shown in figure.Nyquist plot of the product of $G_{1}(s)$ and $G_{2}(s)$ is
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Control Systems
gate2015-ee-2
stability
real-roots
imaginary-roots
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38
GATE Electrical 2014 Set 2 | Question: 33
A discrete system is represented by the difference equation $\begin{bmatrix} X_1(k+1)\\ X_2(k+2) \end{bmatrix}=\begin{bmatrix} a & a-1\\ a+1 & a \end{bmatrix}\begin{bmatrix} X_1(k)\\X_2(k) \end{bmatrix}$ It has initial conditions $X_1(0)$ = $1$ ... $a$ = $1$, are $1\pm j0$ $-1\pm j0$ $\pm 1+j0$ $0\pm j1$
A discrete system is represented by the difference equation$\begin{bmatrix} X_1(k+1)\\ X_2(k+2) \end{bmatrix}=\begin{bmatrix} a & a-1\\ a+1 & a \end{bmatrix}\begin{bmatri...
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Control Systems
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39
GATE Electrical 2014 Set 3 | Question: 45
Consider the system described by following state space equations $\begin{vmatrix} \dot{x_1}\\ \dot{x_2} \end{vmatrix}=\begin{vmatrix} 0 &1 \\ -1 & -1 \end{vmatrix}\begin{vmatrix} x_1\\x_2 \end{vmatrix}+\begin{vmatrix} 0\\1 \end{vmatrix}u$ ... $u$ is unit step input, then the steady state error of the system is $0$ $1/2$ $2/3$ $1$
Consider the system described by following state space equations$\begin{vmatrix} \dot{x_1}\\ \dot{x_2} \end{vmatrix}=\begin{vmatrix} 0 &1 \\ -1 & -1 \end{vmatrix}\begin{v...
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Control Systems
gate2014-ee-3
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GATE Electrical 2014 Set 3 | Question: 18
A single-input single-output feedback system has forward transfer function $G(s)$ and feedback transfer function $H(s)$. It is given that $|G(s)H(s)|< 1$ . Which of the following is true about the stability of the system? The ... are in left half of the s-plane It is not possible to say whether or not the system is stable from the information given
A single-input single-output feedback system has forward transfer function $G(s)$ and feedback transfer function $H(s)$. It is given that $|G(s)H(s)|< 1$ . Which of the f...
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