Recent activity in Signals and Systems

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The Laplace Transform of $f(t)=e^{2t} \sin (5t)(ut)$ is $\dfrac{5}{s^{2}-4s+29} \\ $$\dfrac{5}{s^{2}+5} \\ $$\dfrac{s-2}{s^{2}-4s+29} \\$$\dfrac{5}{s +5}$
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The two signals $S1$ and $S2$, shown in figure, are applied to $Y$ and $X$ deflection plates of an oscilloscope.The waveform displayed on the screen is
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The impulse response a the system is $h(t)=t\:u(t).$ For an input $u(t-1)$, the output is$\dfrac{t^2}{2}u(t) \\$$\dfrac{t(t-1)}{2}u(t-1) \\$$\dfrac{(t-1)^2}{2}u(t-1) \\$$...
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For the signal $f(t)=3 \sin8 \pi t+6 \sin 12\pi t+ \sin14\pi t$ , the minimum sampling frequency (in $Hz$) satisfying the Nyquist criterion is _________.
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Let $X(z)=\dfrac{1}{1-z^{-3}}$ be the $Z$ – transform of a causal signal $x[n]$ Then, the values of $x $ and $x[3]$ are$0$ and $0$$0$ and $1$$1$ and $0$$1$ and $1$
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For a periodic signal $v(t) = 30 \sin100t +10 \cos 300t + 6 \sin (500t+\pi /4)$, the fundamental frequency in $rad/s$ is$100$$300$$500$$1500$
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The impulse response of a continuous time system is given by $h(t)=\delta (t-1)+\delta (t-3).$ The value of the step response at $t=2$ is$0$$1$$2$$3$
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Consider an $LTI$ system with impulse response $h(t)=e^{-5t}u(t)$ . If the output of the system is $y(t)=e^{-3t}u(t)-e^{-5t}u(t)$ then the input, $x(t)$, is given by$e^{...
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