Recent questions tagged impulse-response / GO Electrical

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GATE Electrical 2013 | Question: 41
The impulse response of a continuous time system is given by $h(t)=\delta (t-1)+\delta (t-3).$ The value of the step response at $t=2$ is $0$ $1$ $2$ $3$

The impulse response of a continuous time system is given by $h(t)=\delta (t-1)+\delta (t-3).$ The value of the step response at $t=2$ is$0$$1$$2$$3$

piyag476

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piyag476 asked Feb 11, 2017

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GATE Electrical 2013 | Question: 3
Assuming zero initial condition, the response $y(t)$ of the system given below to a unit step input $u(t)$ is? $u(t) \\$ $t\:u(t) \\$ $\dfrac{t^2}{2}u(t) \\$ $e^{-t}u(t)$

Assuming zero initial condition, the response $y(t)$ of the system given below to a unit step input $u(t)$ is? $u(t) \\$$t\:u(t) \\$$\dfrac{t^2}{2}u(t) \\$$e^{-t}u(t)$

piyag476

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piyag476 asked Feb 11, 2017

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GATE Electrical 2014 Set 2 | Question: 10
Consider an $LTI$ system with impulse response $h(t)=e^{-5t}u(t)$ . If the output of the system is $y(t)=e^{-3t}u(t)-e^{-5t}u(t)$ then the input, $x(t)$, is given by $e^{-3t}u(t)$ $2e^{-3t}u(t)$ $e^{-5t}u(t)$ $2e^{-5t}u(t)$

Consider an $LTI$ system with impulse response $h(t)=e^{-5t}u(t)$ . If the output of the system is $y(t)=e^{-3t}u(t)-e^{-5t}u(t)$ then the input, $x(t)$, is given by$e^{...

makhdoom ghaya

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makhdoom ghaya asked Feb 11, 2017

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GATE Electrical 2015 Set 2 | Question: 34
For linear time invariant systems, that are Bounded Input Bounded Output stable, which one of the following statements is TRUE? The impulse response will be integrable, but may not be absolutely integrable. The unit impulse response will have finite support. The unit step response will be absolutely integrable. The unit step response will be bounded

For linear time invariant systems, that are Bounded Input Bounded Output stable, which one of the following statements is TRUE?The impulse response will be integrable, bu...

makhdoom ghaya

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makhdoom ghaya asked Feb 11, 2017

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GATE Electrical 2015 Set 1 | Question: 10
The impulse response $g(t)$ of a system, $G$, is as shown in Figure $(a)$. What is the maximum value attained by the impulse response of two cascaded blocks of $G$ as shown in Figure $(b)$? $\dfrac{2}{3} \\$ $\dfrac{3}{4} \\$ $\dfrac{4}{5} \\$ $1$

The impulse response $g(t)$ of a system, $G$, is as shown in Figure $(a)$. What is the maximum value attained by the impulse response of two cascaded blocks of $G$ as sho...

makhdoom ghaya

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makhdoom ghaya asked Feb 11, 2017

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GATE Electrical 2016 Set 2 | Question: 28
Let $x_{1}(t)\leftrightarrow X_{1}(\omega )$ and $x_{2}(t)\leftrightarrow X_{2}(\omega )$ be two signals whose Fourier Transforms are as shown in the figure below. In the figure, $h(t)=e^{-2|t|}$ denotes the impulse response. For the system shown above ... can be uniquely reconstructed from its samples, is $2B_{1}$ $2(B_{1}+B_{2})$ $4(B_{1}+B_{2})$ $\infty$

Let $x_{1}(t)\leftrightarrow X_{1}(\omega )$ and $x_{2}(t)\leftrightarrow X_{2}(\omega )$ be two signals whose Fourier Transforms are as shown in the figure below. In the...

makhdoom ghaya

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makhdoom ghaya asked Jan 29, 2017

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GATE Electrical 2016 Set 2 | Question: 18
Consider a linear time-invariant system with transfer function $H(s)=\frac{1}{(s+1)}$ If the input is $\cos(t)$ and the steady state output is $A \cos(t+\alpha)$ then the value of $A$ is _________.

Consider a linear time-invariant system with transfer function$H(s)=\frac{1}{(s+1)}$If the input is $\cos(t)$ and the steady state output is $A \cos(t+\alpha)$ then the v...

makhdoom ghaya

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makhdoom ghaya asked Jan 29, 2017

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GATE Electrical 2016 Set 1 | Question: 35
The output of a continuous-time, linear time-invariant system is denoted by $T\left\{x(t)\right\}$ where $x(t)$ is the input signal. A signal $z(t)$ is called eigen-signal of the system $T$, when $T\left\{z(t)\right\}=\gamma z(t)$ ... $\cos(t)$ is not $\cos(t)$ and $\sin(t)$are both eigen-signals with identical eigenvalues

The output of a continuous-time, linear time-invariant system is denoted by $T\left\{x(t)\right\}$ where $x(t)$ is the input signal. A signal $z(t)$ is called eigen-signa...

makhdoom ghaya

9.4k points

makhdoom ghaya asked Jan 29, 2017