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Refer to the four circuits shown.

Which one of the following options for $\mathrm{k}_{1}, \mathrm{k}_{2}, \mathrm{k}_{3}$, and $\mathrm{k}_{4}$ makes all of them realizable?

  1. $k_{1}=1, k_{4}=-1 / 3$, for all values of $k_{2}$ and $k_{3}$
  2. $k_{2}=-2, k_{3}=+1 / 3$, for all values of $k_{1}$ and $k_{4}$
  3. $\mathrm{k}_{1}=2, \mathrm{k}_{2}=0.5, \mathrm{k}_{3}=-2 / 3, \mathrm{k}_{4}=-3$
  4. $\mathrm{k}_{1}=2, \mathrm{k}_{2}=-0.5, \mathrm{k}_{3}=-2 / 3, \mathrm{k}_{4}=+3$

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