0 0 votes A single-phase voltage source $v_{s}=325 \sin (2 \pi 50 t) \mathrm{V}$ delivers a current, $i=12 \sin (2 \pi 50 t)+9 \sin (2 \pi 150 t)$ A to a load.The load power factor, correct up to two decimal places, is:$1.00$$0.80$$0.65$$0.57$ Power Systems gate2026-ee electric-circuits power-systems numerical-answers + – gatecse 70 views answer comment Share Follow 0 reply Please log in or register to add a comment.
