0 0 votes An electrical component has voltage drop $v=V_{m} \sin (\omega t)$, when the current through it is $i=I_{m} \sin (\omega t-\theta)$.What is the average power dissipated over a half cycle corresponding to $\omega$?$0$$V_{m} I_{m} \cos \theta$$\frac{V_{m} I_{m}}{2} \cos \theta$$\frac{V_{m} I_{m}}{4} \cos \theta$ Electric Circuits gate2026-ee electric-circuits numerical-answers analog-and-digital-electronics + – gatecse 123 views answer comment Share Follow 0 reply Please log in or register to add a comment.
