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The expected number of trials for first occurrence of a "head" in a biased coin is known to be $4.$ The probability of first occurrence of a "head" in the second trial is ____________(Round off to $3$ decimal places).
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if probability of head is $p$ then expected no of trials to get a head =$\frac{1}{p}=4$

probability of head = $\frac{1}{4}$

probability of not head = $\frac{3}{4}$

first head in second trial, so not head and head=$\frac{3}{4}\frac{1}{4}=0.1875$

 

 

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