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Given a fair six-faced dice where the faces are labelled $\text{‘1’, ‘2’, ‘3’, ‘4’, ‘5’, } \text{and ‘6’,}$
what is the probability of getting a $\text{‘1’}$ on the first roll of the dice and a $\text{‘4'}$ on the second roll? 

  1. $\frac{1}{36}$
  2. $\frac{1}{6}$
  3. $\frac{5}{6}$  
  4. $\frac{1}{3}$
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We have a fair six-sided die. When we roll it:

  • There's a $1$ in $6$ chance $(1/6$ probability) of getting a '$1$' on the first roll.
  • There's also a $1$ in $6$ chance $(1/6$ probability) of getting a '$4$' on the second roll.

Since these rolls are independent events, meaning one doesn't affect the other, we can multiply the probabilities:

$(1/6) * (1/6) = 1/36$

So, the probability of rolling a '$1$' on the first roll and a '$4$' on the second roll is $1/36.$

Correct Answer: A

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