0 0 votes Consider discrete random variables $X$ and $Y$ with probabilities as follows: $$ \begin{array}{l} P(X=0 \text { and } Y=0)=\frac{1}{4} \\ P(X=1 \text { and } Y=0)=\frac{1}{8} \\ P(X=0 \text { and } Y=1)=\frac{1}{2} \\ P(X=1 \text { and } Y=1)=\frac{1}{8} \end{array}$$ Given $X=1$, the expected value of $Y$ is $\frac{1}{4}$ $\frac{1}{2}$ $\frac{1}{8}$ $\frac{1}{3}$ Probability & Statistics gate2025-ee probability-and-statistics numerical-answers + – Shubham Sharma 2 321 views answer comment Share Follow 0 reply Please log in or register to add a comment.
