Recent activity in Transform Theory / GO Electrical

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GATE Electrical 2021 | Question: 32
Let $f(t)$ be an even function, i.e. $f(-t)=f(t)$ for all $t$. Let the Fourier transform of $f(t)$ be defined as $F\left ( \omega \right )=\int\limits_{-\infty }^{\infty }\:f\left ( t \right )e^{-j\omega t}dt$ ... $f\left ( 0 \right )< 1$ $f\left ( 0 \right )> 1$ $f\left ( 0 \right )= 1$ $f\left ( 0 \right )= 0$

Let $f(t)$ be an even function, i.e. $f(-t)=f(t)$ for all $t$. Let the Fourier transform of $f(t)$ be defined as $F\left ( \omega \right )=\int\limits_{-\infty }^{\infty ...

Lakshman Bhaiya

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Lakshman Bhaiya recategorized Apr 11, 2021

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Lakshman Bhaiya

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Lakshman Bhaiya recategorized Apr 11, 2021

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GATE Electrical 2019 | Question: 1
The inverse Laplace transform of $H(s)=\frac{s+3}{s^{2}+2s+1}$ for $t \geq0$ $3te^{-t}+e^{-t}$ $3e^{-t}$ $2te^{-t}+e^{-t}$ $4te^{-t}+e^{-t}$

The inverse Laplace transform of $H(s)=\frac{s+3}{s^{2}+2s+1}$ for $t \geq0$$3te^{-t}+e^{-t}$$3e^{-t}$$2te^{-t}+e^{-t}$$4te^{-t}+e^{-t}$

Lakshman Bhaiya

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Lakshman Bhaiya recategorized Mar 10, 2021

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GATE Electrical 2019 | Question: 13
The output response of a system is denoted as $y(t)$, and its Laplace transform is given by $Y(s)=\frac{10}{s(s^{2}+s+100 \sqrt{2})}$ The steady state value of $y(t)$ is $\frac{1}{10 \sqrt{2}} \\ $ $10 \sqrt{2} \\ $ $\frac{1}{100 \sqrt{2}} \\ $ $100 \sqrt{2}$

The output response of a system is denoted as $y(t)$, and its Laplace transform is given by $$Y(s)=\frac{10}{s(s^{2}+s+100 \sqrt{2})}$$ The steady state value of $y(t)$ i...

Lakshman Bhaiya

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Lakshman Bhaiya recategorized Mar 10, 2021

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GATE Electrical 2018 | Question: 40
The Fourier transform of a continuous-time signal $x(t)$ is given by $X(\omega) = \frac{1}{(10+j \omega)^2}, – \infty < \omega < \infty$, where $j = \sqrt{-1}$ and $\omega$ denoes frequency. Then the value of $\mid \text{ln } x(t) \mid$ at $t=1$ is _________ (up to $1$ decimal place). ($\text{ln}$ denotes the logarithm base $e$)

The Fourier transform of a continuous-time signal $x(t)$ is given by $X(\omega) = \frac{1}{(10+j \omega)^2}, – \infty < \omega < \infty$, where $j = \sqrt{-1}$ and $\om...

Lakshman Bhaiya

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Lakshman Bhaiya recategorized Mar 10, 2021

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GATE Electrical 2015 Set 2 | Question: 4
The Laplace transform of $f(t)= 2\sqrt{t/\pi}$ is $s^{-3/2}$. The Laplace transform of $g(t)=\sqrt{1/\pi t}$ is. $3s^{-5/2} /2$ $s^{-1/2}$ $s^{1/2}$ $s^{3/2}$

The Laplace transform of $f(t)= 2\sqrt{t/\pi}$ is $s^{-3/2}$. The Laplace transform of $g(t)=\sqrt{1/\pi t}$ is.$3s^{-5/2} /2$$s^{-1/2}$$s^{1/2}$$s^{3/2}$

Lakshman Bhaiya

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Lakshman Bhaiya recategorized Mar 9, 2021

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GATE Electrical 2014 Set 3 | Question: 5
A function $f(t)$ is shown in the figure. The Fourier transform $F(\omega)$ of $f(t)$ is real and even function of $\omega$ real and odd function of $\omega$ imaginary and odd function of $\omega$ imaginary and even function of $\omega$

A function $f(t)$ is shown in the figure.The Fourier transform $F(\omega)$ of $f(t)$ isreal and even function of $\omega$real and odd function of $\omega$imaginary and od...

Lakshman Bhaiya

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Lakshman Bhaiya recategorized Mar 8, 2021

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GATE Electrical 2012 | Question: 42
The Fourier transform of a signal $h(t)$ is $H(j \omega) = (2 \cos \omega) (\sin 2 \omega )/ \omega$. The value of $h(0)$ is $1/4$ $1/2$ $1$ $2$

The Fourier transform of a signal $h(t)$ is $H(j \omega) = (2 \cos \omega) (\sin 2 \omega )/ \omega$. The value of $h(0)$ is$1/4$$1/2$$1$$2$

Lakshman Bhaiya

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Lakshman Bhaiya recategorized Mar 7, 2021

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GATE Electrical 2012 | Question: 15
The unilateral Laplace transform of $f(t)$ is $\dfrac{1}{s^2+s+1}$. The unilateral Laplace transform of $t f(t)$ is $ – \dfrac{s}{(s^2+s+1)^2} \\ $ $ – \dfrac{2s+1}{(s^2+s+1)^2} \\$ $ \dfrac{s}{(s^2+s+1)^2} \\$ $ \dfrac{2s+1}{(s^2+s+1)^2}$

The unilateral Laplace transform of $f(t)$ is $\dfrac{1}{s^2+s+1}$. The unilateral Laplace transform of $t f(t)$ is$ – \dfrac{s}{(s^2+s+1)^2} \\ $$ – \dfrac{2s+1}{(s^...

Lakshman Bhaiya

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Lakshman Bhaiya recategorized Mar 7, 2021