0 votes 0 votes The Laplace transform of $f(t)= 2\sqrt{t/\pi}$ is $s^{-3/2}$. The Laplace transform of $g(t)=\sqrt{1/\pi t}$ is. $3s^{-5/2} /2$ $s^{-1/2}$ $s^{1/2}$ $s^{3/2}$ Transform Theory gate2015-ee-2 transform-theory laplace-transform + – makhdoom ghaya asked Feb 11, 2017 • recategorized Mar 9, 2021 by Lakshman Bhaiya makhdoom ghaya 9.4k points answer comment Share See all 0 reply Please log in or register to add a comment.