GATE Electrical 2018 | GA | Question: 7

Question

In a certain code, $AMCF$ is written as $EQGJ$ and $NKUF$ is written as $ROYJ.$ How will $DHLP$ be written in that code$?$

• A. $RSTN$   
• B. $TLPH$     
• C. $HLPT$   
• D. $XSVR$

Comments

C) HLPT

---

c ans is correct because it follow +4 increment

---

Will give you a hint, so that you can think and then solve yourselves. You can use a trick in this question i.e of EJOTY(5,10,15,20,25). Now, Just compare A from AMCF, E from EQGJ. The difference is of only 4 spaces. Now do yourselves.

Final answer is C. HLPT

---

In this type of questions don't waste time in writing. Take easy alphabet and find pattern here 4 is difference now do option elimination

Answer 1

 $AMFC= EQGJ$ 

$NKUF= ROYJ$

It is clear from both the words that corresponding alphabets are obtained by incrementing particular letter by 4, for ex: $A+4 = E, N+4= R$.

So, $D+4= H, H+4=L, L+4=P, P+4=T$

Hence option c) is correct

Answer 2

As, AMCF = EQGJ

& NKUF = ROYJ

Then, DHLP must be equal to HLPT

As every letter here  is equal to a letter which is greater than 4 alphabetically

Comments

Nice

Answer 3

In the given code, each alphabet is +4 in sequence.

$AMCF$ can be written as $EQGJ$. its patterns are as follows:

• $A+4=E$
• $M+4=Q$
• $C+4=G$
• $F+4=H$

$NKUF$ is written as $ROYJ$. its patterns are as follows:

• $N+4=4$
• $K+4=O$
• $U+4=Y$
• $F+4=J$

In the same way, $DHLP$ can be written as follows;

• $D+4=H$
• $H+4=L$
• $L+4=P$
• $P+4=T$

Therefore $option(3)$ is correct.