13 13 votes In four-digit integer numbers from $1001$ to $9999$, the digit group $\text{“37”}$ (in the same sequence) appears ________ times. $270$ $279$ $280$ $299$ Analytical Aptitude gate2020-ee analytical-aptitude logical-reasoning sequence-series + – go_editor 4.4k views answer comment Share Follow 0 reply Please log in or register to add a comment.
Best answer 27 27 votes Ans C Number of four digit numbers from $1001$ to $9999 = 8999.$ Number of times digit group $“37”$ appears is given by: $\_ \;\;\_\;\;3 \;\;7 \to \text{(1 to 9) (0 to 9)} \to 9 \cdot 10 = 90$ $\_\;\;3 \;\;7\; \_ \to \text{(1 to 9) (0 to 9)} \to 9 \cdot 10 = 90$ $3 \;\;7\;\_\;\; \_ \to \text{(0 to 9) (0 to 9)} \to 10\cdot 10 = 100$ Total count $=90+90+100 = 280.$ Correct option: C If the question was for finding the number of integers in which $“37”$ appeared then answer would be $279$ because in the above counting we double counted for $3737$, first in $\_ \;\;\_\;\; 3\; \;7$ and second in $3\; \; 7\; \_ \;\;\_ .$ vijayp_ answered Aug 12, 2020 • edited Apr 11, 2021 by Arjun vijayp_ comment Share Follow See all 3 Comments 3 3 Comments reply Tharun_Kumar commented Apr 11, 2021 reply Follow flag What’s the use to write 4th line (3737 is counted twicw ….) 2 2 replyShare Arjun commented Apr 11, 2021 reply Follow flag Edited now. 2 2 replyShare nobodysomebody commented Dec 2, 2025 i moved by Arjun May 13 reply Follow flag very well explained 0 0 replyShare Please log in or register to add a comment.
