0 0 votes A series $RL$ circuit is excited at $t = 0$ by closing a switch as shown in the figure. Assuming zero initial conditions, the value of $\dfrac{d^{2}i}{dt^{2}}$ at $t=0^{+}$ is $\dfrac{V}{L} \\$ $\dfrac{-V}{R} \\$ $0 \\$ $\dfrac{-RV}{L^{2}}$ Electric Circuits gate2015-ee-2 switching rl-circuit zero-initial-condition + – Misbah Ghaya 405 views answer comment Share Follow 0 reply Please log in or register to add a comment.
