The pattern of the unit's digits of powers of $3:$
- $3^1 = 3$
- $3^2 = 9$
- $3^3 = 7$
- $3^4 = 1$
The pattern repeats every $4$ powers of $3.$
The pattern of the unit's digits of powers of $7:$
- $7^1 = 7$
- $7^2 = 9$
- $7^3 = 3$
- $7^4 = 1$
The pattern repeats every $4$ powers of $7.$
Now, Unit digit of $3^{999} \times 7^{1000} = \underbrace{3^{4{(249)}}}_{\text{Unit digit = 1}} \times 3^3 \times \underbrace{7^{4(250)}}_{\text{Unit digit = 1}} = 1 \times 7 \times 1 = 7$
So, the unit's digit of $3^{999} \times 7^{1000}$ is $7.$
Correct Answer: A