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A $\text{MOD 2}$ and a $\text{MOD 5}$ up-counter when cascade together results in a $\text{MOD}$ _________________ counter. (in integer)

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Answer: 10

If MOD $a$, MOD $b$, …, MOD $n$ counter are cascaded together. The resultant counter will be of 

MOD ($a*b*..*n$).

Therefore, when MOD 2 and MOD 5 counter are cascaded together the resultant counter will be of MOD ($2*5$) = MOD $10$

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