A $\text{MOD 2}$ and a $\text{MOD 5}$ up-counter when cascade together results in a $\text{MOD}$ _________________ counter. (in integer)

If MOD $a$, MOD $b$, …, MOD $n$ counter are cascaded together. The resultant counter will be of
MOD ($a*b*..*n$).
Therefore, when MOD 2 and MOD 5 counter are cascaded together the resultant counter will be of MOD ($2*5$) = MOD $10$