GATE Electrical 2018 | Question: 14

Question

In the logic circuit shown in the figure, $Y$ is given by

• A. $Y=ABCD$
• B. $Y=(A+B)(C+D)$
• C. $Y=A+B+C+D$
• D. $Y=AB+CD$

Answer 1

Y = ((AB)^C . (CD)^C)^C = ((AB)^C)^C+ ((CD)^C)^C = AB + CD

Hence, D is correct :)