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In the summer of $2012,$ in New Delhi, the mean temperature of Monday to Wednesday was $41^{\circ}C$ and of Tuesday to Thursday was $43^{\circ}C$. If the temperature on Thursday was $15\%$ higher than that of Monday, then the temperature in $^{\circ}C$ on Thursday was

  1. $40$
  2. $43$
  3. $46$
  4. $49$

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Option C is correct answer

Sum of temperatures for Monday ($M$), Tuesday ($T$), and Wednesday ($W$)

$M + T + W = 41 \times 3 = 123^\circ\text{C}$.                ------> (1)

Sum of temperatures for Tuesday ($T$), Wednesday ($W$), and Thursday ($Th$)

$T + W + Th = 43 \times 3 = 129^\circ\text{C}$.              --------> (2)

Now from equation (1) and (2) , we do

$(T + W + Th) - (M + T + W) = 129 - 123$

$Th - M = 6^\circ\text{C}$

it is given that Thursday's temperature is 15% higher than Monday's,

$Th = M + 0.15M = 1.15M$            -----> (3)

$Th - M = 0.15M$

$0.15M = 6$

$M = \frac{6}{0.15} = 40^\circ\text{C}$

From equation (3) Thursday's temperature ($Th$)

$Th = 1.15 \times 40 = 46^\circ\text{C}$

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