11 11 votes The ration of the number of boys and girls who participated in an examination is $4:3.$ The total percentage of candidates who passed the examination is $80$ and the percentage of girls who passed the exam is $90.$ The percentage of boys who passed is _______. $55.50$ $72.50$ $80.50$ $90.00$ Quantitative Aptitude gate2019-ee general-aptitude quantitative-aptitude ratio-proportion percentage + – Arjun 1.7k views answer comment Share Follow See 1 comment 1 1 comment reply Kiyoshi commented Nov 27, 2021 i moved by Arjun May 18 reply Follow flag Total no. of students = x Boys = 4x / 7 Girls = 3x / 7 Let B is the percentage of boys passed. (4x / 7) * B + (3x / 7)*0.90 = x*0.80 B = 0.725 percentage of boys passed = 72.50 5 5 replyShare Please log in or register to add a comment.
Best answer 6 6 votes $\text{Percentage of passed students} = \frac{\text{Percentage of boys passed} \times \text{#boys}+ \text{Percentage of girls passed}\times\text{#girls}}{\text{Total number of students}}$ Taking total number of students as $x$ and from the given statements, $80 = \frac{\text{Percentage of boys passed} \times \frac{4}{4+3}x + 90 \times \frac{3}{4+3}x}{x}$ $\implies80 \times 7 = 4 \times \text{Percentage of boys passed} + 3 \times 90 $ $\implies \text{Percentage of boys passed} = \frac{560-270}{4} = \frac{290}{4} = 72.5$ Correct Answer: B Arjun answered Jun 1, 2019 • moved May 18 by Arjun Arjun comment Share Follow 0 reply Please log in or register to add a comment.
20 20 votes Let total candidates attempting the exam be $70$. In these Boys:Girls are in ratio $4:3$ $\Rightarrow$ There are $40$ boys and $30$ girls. $80$% of the total candidates passed the exam = $\frac{80}{100}*70$ = $56$ $90$% of the girls passed the exam = $\frac{90}{100}*30$ = $27$ So Number of boys who passed the exam = total candidates who passed the exam – total girls who passed the exam = $56-27$ =$29$ $\therefore$ Percentage of boys who passed the exam = $\frac{29}{40}*100$ = $72.50$ So Option B $72.50$ is the correct answer. Satbir answered May 17, 2019 • moved May 18 by Arjun Satbir comment Share Follow 0 reply Please log in or register to add a comment.
6 6 votes $\text{Let no of boys B = 4k ,G = 3k and total students = 7k }$ $\text{total passed students} = 0.8 * 7k$ $\implies \text{0.9 * 3k + X * 4k } = \text{0.8 * 7k}$ $\implies X = 0.725$ $\therefore \text{pass percentage of boys } X = 72.5$ subbus answered May 9, 2020 • moved May 18 by Arjun subbus comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Y= 0.75 X (given) Let, Y= total no. of girls and X= total no. of Boys 80% of the total students passed the exam successfully; (X+Y)*0.8 And 90% of the girls passed the exam too; 0.9*Y thus we can write, (X+Y)*0.8 = 0.9*Y + X* (percentage of the boys who passed the exam) 1.75*0.8*X = X( 0.9*0.75 + Percentage of the boys who passed the exam) Percentage of the boys who passed the exam = 72.5% ashishrajmin answered Jul 29, 2022 ashishrajmin comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes B = 72.5 deepakcec answered Jun 17 deepakcec comment Share Follow 0 reply Please log in or register to add a comment.