0 0 votes The input voltage $v(t)$ and current $i(t)$ of a converter are given by, $\begin{array}{l} v(t)=300 \sin (\omega t) V \\ i(t)=10 \sin \left(\omega t-\frac{\pi}{6}\right)+2 \sin \left(3 \omega t+\frac{\pi}{6}\right)+\sin \left(5 \omega t+\frac{\pi}{2}\right) A \end{array}$ where, $\omega=2 \pi \times 50 \: \mathrm{rad} / \mathrm{s}$. The input power factor of the converter is closest to $0.845$ $0.867$ $0.887$ $1.0$ Power Electronics gate2025-ee power-electronics numerical-answers + – Shubham Sharma 2 326 views answer comment Share Follow 0 reply Please log in or register to add a comment.
