0 0 votes A function $y(t)$, such that $y(0)=1$ and $y(1)=3e^{-1}$, is a solution of the differential equation $\dfrac{d^{2}y}{dt^{2}}+2\dfrac{dy}{dt}+y=0$. Then $y(2)$ is $5e^{-1}$ $5e^{-2}$ $7e^{-1}$ $7e^{-2}$ Differential Equations gate2016-ee-1 differential-equations numerical-answers + – Misbah Ghaya 278 views answer comment Share Follow 0 reply Please log in or register to add a comment.
