0 votes 0 votes The Laplace Transform of $f(t)=e^{2t} \sin (5t)(ut)$ is $\dfrac{5}{s^{2}-4s+29} \\ $ $\dfrac{5}{s^{2}+5} \\ $ $\dfrac{s-2}{s^{2}-4s+29} \\$ $\dfrac{5}{s +5}$ Signals and Systems gate2016-ee-1 unit-step-function fourier-transform shifting-theorems + – makhdoom ghaya asked Jan 29, 2017 • edited Oct 3, 2020 by go_editor makhdoom ghaya 9.4k points answer comment Share See all 0 reply Please log in or register to add a comment.