2 2 votes A surveyor has to measure the horizontal distance from her position to a distant reference point $\text{C}$. Using her position as the center, a $200 \mathrm{~m}$ horizontal line segment is drawn with the two endpoints $\text{A}$ and $\text{B}$. Points $\text{A}$, $\text{B}$, and $\text{C}$ are not collinear. Each of the angles $\angle \mathrm{CAB}$ and $\angle \mathrm{CBA}$ are measured as $87.8^{\circ}$. The distance (in $\mathrm{m}$ ) of the reference point $\mathrm{C}$ from her position is nearest to $2603$ $2606$ $2306$ $2063$ Quantitative Aptitude gate2024-ee quantitative-aptitude geometry + – Arjun 1.5k views answer comment Share Follow See 1 comment 1 1 comment reply Malay Nirav commented Feb 21, 2024 reply Follow flag Given order of options are incorrect. Data is right but order is incorrect. 0 0 replyShare Please log in or register to add a comment.
8 8 votes \[XC=tan(87.8^\circ)*100=2603.073\]Hence, Option A is the correct answer. Sujith K answered Aug 15, 2024 • moved May 13 by Arjun Sujith K comment Share Follow 0 reply Please log in or register to add a comment.