0 0 votes A long conducing cylinder having a radius $’b’$ is placed along the $z$ axis. The current density is $J = J_{a} \:r^{3}\:\hat{z}$ for the region $r< b$ where $r$ is the distance in the radial direction. The magnetic field intensity $\text{(H)}$ for the region inside the conductor (i.e. for $r< b$) is $\dfrac{J_{a}}{4}\:r^{4}$ $\dfrac{J_{a}}{3}\:r^{3}$ $\dfrac{J_{a}}{5}\:r^{4}$ $J_{a}\:r^{3}$ Electromagnetic Fields gate2022-ee electromagnetic-fields numerical-answers + – Arjun 395 views answer comment Share Follow 0 reply Please log in or register to add a comment.