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The interior angle between the sides of the polygon $ = \frac{(n-2) \times 180^{\circ}}{n},$ where $n = $ number of sides of the polygon.

Here, $n = 10,$  therefore the interior angle between the sides of the polygon $ = \frac{(10-2) \times 180^{\circ}}{10}$

$\qquad = 8 \times 18^{\circ} = 144^{\circ}.$

So, the correct answer is $(D).$
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4 4 votes
answer 144

solution- (n-2)*180=(10-2)*180=1440

where n=10 which are side decagon.

so interior angle

1440/10=144

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