8 8 votes Given a semicircle with $\text{O}$ as the centre, as shown in the figure, the ratio $\dfrac{\overline{AC}+\overline{CB}}{\overline{AB}}$ is _______, where $\overline{AC}$, $\overline{CB}$ and $\overline{AB}$ are chords. $\sqrt{2}$ $\sqrt{3}$ $2$ $3$ Quantitative Aptitude gate2020-ee quantitative-aptitude geometry circle + – go_editor 1.8k views answer comment Share Follow 0 reply Please log in or register to add a comment.
Best answer 10 10 votes Ans A Given O as the center. AB is the diameter. Let Diameter = $2r$ Then $ AO = OB = r $, $ CO = r $ Semicircle. $\angle COB = \angle COA= 90^{\circ}$, Applying Pythagoras Theorem in $\triangle COB, \triangle COA$ $CB = CA = \sqrt{2}r$ Putting in given equation.$\frac{\overline{AC }+ \overline{CB}}{\overline{AB}} = \frac{\sqrt{2}r +\sqrt{2}r }{2r} = \frac{2\sqrt{2}r }{2r} = \frac{\sqrt{2} }{1}=\sqrt{2}$ vijayp_ answered Aug 12, 2020 • selected Apr 5, 2021 by gatecse vijayp_ comment Share Follow 0 reply Please log in or register to add a comment.