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Recent questions tagged boolean-algebra
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votes
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1
GATE Electrical 2019 | Question: 35
The output expression for the Karnaugh map shown below is $Q \bar{R} +S$ $Q \bar{R} + \bar{S}$ $QR+S$ $Q R +\bar{S}$
Arjun
asked
in
Analog and Digital Electronics
Feb 12, 2019
by
Arjun
9.3k
points
gate2019-ee
analog-and-digital-electronics
boolean-algebra
k-map
0
votes
0
answers
2
GATE Electrical 2012 | Question: 7
In the sum of products function $f(X,Y,Z) = \Sigma(2,3,4,5)$, the prime implicants are $\overline{X}Y, X \overline{Y}$ $\overline{X}Y, X \overline{Y}\overline{Z}, X \overline{Y}Z$ $\overline{X} Y \overline{Z}, \overline{X}YZ, X \overline{Y}$ $\overline{X} Y \overline{Z}, \overline{X}YZ, X \overline{Y} \overline{Z}, X \overline{Y}Z$
Andrijana3306
asked
in
Analog and Digital Electronics
Mar 24, 2018
by
Andrijana3306
1.4k
points
gate2012-ee
analog-and-digital-electronics
boolean-algebra
sum-of-products
0
votes
0
answers
3
GATE Electrical 2018 | Question: 37
Digital input signals A, B, C with A as the MSB and C as the LSB are used to realize the Boolean function $F=m_0+m_2+m_3+m_5+m_7$, where $m_i$ denotes the $i$ th minterm. In addition, $F$ has a don't care for $m_1$. The simplified expression for $F$ is given by ... $\overline{A}+C$ $\overline{C}+A$ $\overline{A} C + BC + A \overline{C}$
Arjun
asked
in
Analog and Digital Electronics
Feb 19, 2018
by
Arjun
9.3k
points
gate2018-ee
analog-and-digital-electronics
boolean-algebra
0
votes
1
answer
4
GATE Electrical 2018 | Question: 14
In the logic circuit shown in the figure, $Y$ is given by $Y=ABCD$ $Y=(A+B)(C+D)$ $Y=A+B+C+D$ $Y=AB+CD$
Arjun
asked
in
Analog and Digital Electronics
Feb 19, 2018
by
Arjun
9.3k
points
gate2018-ee
analog-and-digital-electronics
logic-gates
boolean-algebra
0
votes
0
answers
5
GATE Electrical 2017 Set 1 | Question: 36
The output expression for the Karnaugh map shown below is $B \overline{D}+BCD$ $B \overline{D}+AB$ $\overline{B}D+ABC$ $B \overline{D}+ABC$
Arjun
asked
in
Analog and Digital Electronics
Feb 27, 2017
by
Arjun
9.3k
points
gate2017-ee-1
analog-and-digital-electronics
boolean-algebra
k-map
0
votes
0
answers
6
GATE Electrical 2017 Set 1 | Question: 13
The Boolean expression $AB+A\bar{C}+BC$ simplifies to $BC + A\bar{C}$ $AB + A\bar{C} + B$ $AB + A\bar{C}$ $AB + BC$
Arjun
asked
in
Analog and Digital Electronics
Feb 27, 2017
by
Arjun
9.3k
points
gate2017-ee-1
analog-and-digital-electronics
boolean-algebra
0
votes
0
answers
7
GATE Electrical 2015 Set 1 | Question: 38
$f(A, B, C, D) = \pi M(0,1,3,4,5,7,9,11,12,13,14,15)$ is a maxterm representation of a Boolean function $f (A, B, C, D)$ where $A$ is the $MSB$ and $D$ is the $LSB$ ... $(B+\overline{C}+D) (A+\overline{B}+\overline{C}+D) (\overline{A}+B+C+D)$
makhdoom ghaya
asked
in
Analog and Digital Electronics
Feb 12, 2017
by
makhdoom ghaya
9.3k
points
gate2015-ee-1
logic-gates
boolean-algebra
0
votes
0
answers
8
GATE Electrical 2015 Set 1 | Question: 15
In the $4 \times 1$ multiplexer, the output $F$ is given by $F = A \oplus B$. Find the required input $'I_{3}, I_{2}, I_{1}, I_{0}'$. $1010$ $0110$ $1000$ $1110$
makhdoom ghaya
asked
in
Analog and Digital Electronics
Feb 12, 2017
by
makhdoom ghaya
9.3k
points
gate2015-ee-1
multiplexer
boolean-algebra
0
votes
0
answers
9
GATE Electrical 2016 Set 2 | Question: 26
The Boolean expression $\overline{(a+\bar{b}+c+\bar{d})+(b+\bar{c})}$ simplifies to $1$ $\overline{a.b}$ $a.b$ $0$
makhdoom ghaya
asked
in
Analog and Digital Electronics
Jan 30, 2017
by
makhdoom ghaya
9.3k
points
gate2016-ee-2
analog-and-digital-electronics
boolean-algebra
0
votes
0
answers
10
GATE Electrical 2016 Set 2 | Question: 1
The output expression for the Karnaugh map shown below is $A+\bar{B}$ $A+\bar{C}$ $\bar{A}+\bar{C}$ $\bar{A}+C$
makhdoom ghaya
asked
in
Analog and Digital Electronics
Jan 30, 2017
by
makhdoom ghaya
9.3k
points
gate2016-ee-2
analog-and-digital-electronics
boolean-algebra
k-map
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