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Recent questions tagged boolean-algebra

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GATE Electrical 2019 | Question: 35
The output expression for the Karnaugh map shown below is $Q \bar{R} +S$ $Q \bar{R} + \bar{S}$ $QR+S$ $Q R +\bar{S}$
The output expression for the Karnaugh map shown below is$Q \bar{R} +S$$Q \bar{R} + \bar{S}$$QR+S$$Q R +\bar{S}$
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GATE Electrical 2018 | Question: 14
In the logic circuit shown in the figure, $Y$ is given by $Y=ABCD$ $Y=(A+B)(C+D)$ $Y=A+B+C+D$ $Y=AB+CD$
In the logic circuit shown in the figure, $Y$ is given by$Y=ABCD$$Y=(A+B)(C+D)$$Y=A+B+C+D$$Y=AB+CD$
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GATE Electrical 2017 Set 1 | Question: 36
The output expression for the Karnaugh map shown below is $B \overline{D}+BCD$ $B \overline{D}+AB$ $\overline{B}D+ABC$ $B \overline{D}+ABC$
The output expression for the Karnaugh map shown below is$B \overline{D}+BCD$$B \overline{D}+AB$$\overline{B}D+ABC$$B \overline{D}+ABC$
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GATE Electrical 2017 Set 1 | Question: 13
The Boolean expression $AB+A\bar{C}+BC$ simplifies to $BC + A\bar{C}$ $AB + A\bar{C} + B$ $AB + A\bar{C}$ $AB + BC$
The Boolean expression $AB+A\bar{C}+BC$ simplifies to$BC + A\bar{C}$$AB + A\bar{C} + B$$AB + A\bar{C}$$AB + BC$
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GATE Electrical 2015 Set 1 | Question: 15
In the $4 \times 1$ multiplexer, the output $F$ is given by $F = A \oplus B$. Find the required input $'I_{3}, I_{2}, I_{1}, I_{0}'$. $1010$ $0110$ $1000$ $1110$
In the $4 \times 1$ multiplexer, the output $F$ is given by $F = A \oplus B$. Find the required input $'I_{3}, I_{2}, I_{1}, I_{0}'$.$1010$$0110$$1000$$1110$
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