0 0 votes The maximum value of $f(x) = x^3-9x^2+24x+5$ in the interval $[1,6]$ is $21$ $25$ $41$ $46$ Calculus gate2012-ee calculus maxima-minima + – Andrijana3306 517 views answer comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes f'(x)=3x^2-18x+24=0 x^2-6x+8=0 x=4,2 f(2)=8-36+48+5=25 f(4)=64-144+96+5=21 so B Anmol VG answered Sep 7, 2024 Anmol VG comment Share Follow See 1 comment 1 1 comment reply legend_of_cse commented Aug 23, 2025 reply Follow flag I think you are not checking at the endpoint ... f(6) =41 ...so answer will be option C... Reason : f(x) is polynomial function ,it is both continous and differenciable ..if u check the nature of first derivatives of f(x) ...it will convex ..it means maximum we will find at endpoint .... 0 0 replyShare Please log in or register to add a comment.
0 0 votes correct Answer : option C.. { hint: check at endpoint} legend_of_cse answered Aug 23, 2025 legend_of_cse comment Share Follow 0 reply Please log in or register to add a comment.