0 0 votes With initial condition $x(1)=0.5$, the solution of the differential equation $t\dfrac{dx}{dt}+x=t$ is $x=t-\dfrac{1}{2} \\ $ $x=t^2-\dfrac{1}{2} \\ $ $x=\dfrac{t^2}{2} \\$ $x=\dfrac{t}{2}$ Differential Equations gate2012-ee differential-equations + – Andrijana3306 230 views answer comment Share Follow 0 reply Please log in or register to add a comment.
