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With initial condition $x(1)=0.5$, the solution of the differential equation $t\dfrac{dx}{dt}+x=t$ is

  1. $x=t-\dfrac{1}{2} \\ $
  2. $x=t^2-\dfrac{1}{2} \\ $
  3. $x=\dfrac{t^2}{2} \\$
  4. $x=\dfrac{t}{2}$
in Differential Equations recategorized by
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