0 0 votes Minimum of the real valued function $f(x)=(x-1)^{2/3}$ occurs at $x$ equal to $-\infty$ $0$ $1$ $\infty$ Calculus gate2014-ee-2 calculus maxima-minima + – Misbah Ghaya 496 views answer comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Ans :- option CConcept : For real x, (x−1)^2/3= ((x−1^)2)^1/3 = ∣x−1∣^2/3 .This is always ≥0. The smallest possible value of an absolute-power like this is 0, attained when the inside is zero. legend_of_cse answered Aug 23, 2025 legend_of_cse comment Share Follow 0 reply Please log in or register to add a comment.