For the circuit shown below, taking the opamp as ideal, the output voltage $V_{out}$ in terms of the input voltages $V_{1}, V_{2}$ and $V_{3}$ is
- $1.8V_{1} + 7.2V_{2} -V_{3}$
- $2V_{1} + 8V_{2} - 9V_{3}$
- $7.2V_{1} + 1.8V_{2} -V_{3}$
- $8V_{1} + 2V_{2} - 9V_{3}$