This question is easy to imagine, Let $C_1 : \space y =x^2$ and $C_2 : \space y =-x^2-2x-1 = -(x+1)^2$
$C_1$ is a U shaped parabola with minimum at origin
$C_2$ is an inverted ($\cap$) parabola with maximum at -1.
There is no intersection between the two. So Answer is 0.
Regular method, solve the simultaneous equations.
$$\begin{cases} y=x^2 & (1) \\ y=-x^2-2x-1 & (2)\end{cases}$$
you will get $0 =2x^2+2x+1$
Let $\Delta = b^2-4ac = 4-8=-4 \lt0$
Hence roots are imaginary, hence no intersection exists.
Option (A) is accurate.
