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GATE Electrical 2026 | Question: 55

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1 1 vote
The integral
\[
\frac{1}{\pi} \int_{0}^{\infty} \frac{x^{2026}}{\left(1+x^{2026}\right)\left(1+x^{2}\right)} \mathrm{d} x
\]
evaluates to $\_\_\_\_$

(Round off to two decimal places)

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