In the following figure,
\[
\begin{array}{c}
\mathrm{CD}=5 \mathrm{~cm}, \mathrm{BE}=10 \mathrm{~cm}, \mathrm{AE}=12 \mathrm{~cm}, \\
\angle \mathrm{DAB}=\angle \mathrm{DCB} \text {, and } \angle \mathrm{DAE}=\angle \mathrm{DBC}=90^{\circ}
\end{array}
\]
Points $\text{AFCD}$ create a rhombus.
The length of $\mathrm{BF}$ (in $\mathrm{cm}$ ) is
- $3$
- $2$
- $4$
- $6$