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\hline Q.34 & $\begin{array}{l}\text { In the following differential equation, the numerically obtained value of } y(t), \text { at } t=1, \\

\text { is }\end{array}$ \\

\hline$\frac{d y}{d t}=\frac{e^{-\alpha t}}{2+\alpha t}, \quad \alpha=0.01$ and $y(0)=0$ \\

\hline & \\

\hline

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