Recent questions tagged voltage-source / GO Electrical

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GATE Electrical 2013 | Question: 22
Three moving iron type voltmeters are connected as shown below. Voltmeter readings are $V$, $V1$ and $V2$ , as indicated. The correct relation among the voltmeter readings is $V=\dfrac{V1}{\sqrt{2}}+\dfrac{V2}{\sqrt{2}}$ $V =V_1 +V_2$ $V =V_1V_2$ $V =V_2 - V_1$

Three moving iron type voltmeters are connected as shown below. Voltmeter readings are $V$, $V1$ and $V2$ , as indicated. The correct relation among the voltmeter reading...

piyag476

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piyag476 asked Feb 11, 2017

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GATE Electrical 2013 | Question: 2
The transfer function $\dfrac{V2(s)}{V1(s)}$ of the circuit shown below is $\dfrac{0.5s+1}{s+1} \\$ $\dfrac{3s+6}{s+2} \\$ $\dfrac{s+2}{s+1} \\$ $\dfrac{s+1}{s+2}$

The transfer function $\dfrac{V2(s)}{V1(s)}$ of the circuit shown below is$\dfrac{0.5s+1}{s+1} \\$$\dfrac{3s+6}{s+2} \\$$\dfrac{s+2}{s+1} \\$$\dfrac{s+1}{s+2}$

piyag476

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piyag476 asked Feb 11, 2017

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GATE Electrical 2015 Set 1 | Question: 18
The voltages developed across the $3 \Omega$ and $2 \Omega$ resistors shown in the figure are $6 V$ and $2 V$ respectively, with the polarity as marked. What is the power (in Watt) delivered by the $5 V$ voltage source? $5$ $7$ $10$ $14$

The voltages developed across the $3 \Omega$ and $2 \Omega$ resistors shown in the figure are $6 V$ and $2 V$ respectively, with the polarity as marked. What is the power...

makhdoom ghaya

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makhdoom ghaya asked Feb 11, 2017