edited by
0 votes
0 votes

​​​​A $3$-phase, $11 \mathrm{kV}, 10 \mathrm{MVA}$ synchronous generator is connected to an inductive load of power factor $(\sqrt{3} / 2)$ via a lossless line with a per-phase inductive reactance of $5 \Omega$. The per-phase synchronous reactance of the generator is $30 \Omega$ with negligible armature resistance. If the generator is producing the rated current at the rated voltage, then the power factor at the terminal of the generator is

  1. $0.63$ lagging.
  2. $0.87$ lagging.
  3. $0.63$ leading.
  4. $0.87$ leading.
edited by

Please log in or register to answer this question.

Answer: