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Recent questions tagged pauldirac
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GATE201619
The value of $\int_{\infty}^{+\infty} e^{t} \delta (2t2){d}t$, where $\delta (t)$ is the Dirac delta function, is $\frac{1}{2e}$ $\frac{2}{e}$ $\frac{1}{e^{2}}$ $\frac{1}{2e^{2}}$
asked
Jan 30, 2017
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Calculus
by
makhdoom ghaya
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gate2016ee1
pauldirac
operationalcalculus
weaklimit
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