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GATE201427
The switch SW shown in the circuit is kept at position $'1'$ for a long duration. At $t = 0+$, the switch is moved to position $'2'$. Assuming $\mid V_o2\mid > \mid V_o1\mid$, the voltage $v_c$(t) across the capacitor is $V_c (t)=V_{o2}(1e^{t/2RC})V_{o1}$ ... $V_{o2}$+$V_{o1}$)$(1e^{t/2RC})V_{o1}$ $V_c (t)=$($V_{o2}$+$V_{o1}$)$(1e^{t/2RC})+V_{o1}$
asked
Feb 12, 2017
in
Electrical Circuits
by
makhdoom ghaya
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points)
gate2014ee2
switchingschemes
loads
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