Recent questions tagged gain / GO Electrical

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GATE Electrical 2013 | Question: 15
The Bode plot of a transfer function $G(s)$ is shown in the figure below. The gain $\big(20 \log\mid G(s) \mid \big)$ is $32 dB$ and $-8 dB$ at $1$ rad/s and $10$ rad/s respectively. The phase is negative for all $\omega$. Then $G(s)$ is $\dfrac{39.8}{s} \\$ $\dfrac{39.8}{s^2} \\$ $\dfrac{32}{s} \\$ $\dfrac{32}{s^2}$

The Bode plot of a transfer function $G(s)$ is shown in the figure below.The gain $\big(20 \log\mid G(s) \mid \big)$ is $32 dB$ and $-8 dB$ at $1$ rad/s and $10$ rad/s r...

piyag476

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piyag476 asked Feb 11, 2017

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GATE Electrical 2014 Set 2 | Question: 45
For the transfer function $G(s)=\dfrac{5(s+2)}{s(s+0.25)(s^2+4s+25)}$ The values of the constant gain term and the highest corner frequency of the Bode plot respectively are $3.2$ , $5.0$ $16.0$ , $4.0$ $3.2$ , $4.0$ $16.0$ , $5.0$

For the transfer function $$G(s)=\dfrac{5(s+2)}{s(s+0.25)(s^2+4s+25)}$$ The values of the constant gain term and the highest corner frequency of the Bode plot respectivel...

makhdoom ghaya

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makhdoom ghaya asked Feb 11, 2017

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GATE Electrical 2016 Set 2 | Question: 52
The gain at the breakaway point of the root locus of a unity feedback system with open loop transfer function $G(s)=\frac{Ks}{(s-1)(s-4)}$ is $1$ $2$ $5$ $9$

The gain at the breakaway point of the root locus of a unity feedback system with open loop transfer function $G(s)=\frac{Ks}{(s-1)(s-4)}$ is$1$$2$ $5$$9$

makhdoom ghaya

9.4k points

makhdoom ghaya asked Jan 29, 2017