0 votes 0 votes The Fourier transform of a signal $h(t)$ is $H(j \omega) = (2 \cos \omega) (\sin 2 \omega )/ \omega$. The value of $h(0)$ is $1/4$ $1/2$ $1$ $2$ Transform Theory gate2012-ee transform-theory fourier-transform + – Andrijana3306 asked Mar 23, 2018 recategorized Mar 7, 2021 by Lakshman Bhaiya Andrijana3306 1.4k points answer comment Share See all 0 reply Please log in or register to add a comment.