0 votes 0 votes Let $y[n]$ denote the convolution of $h[n]$ and $g[n]$, where $h[n]=(1/2)^n u[n]$ and $g[n]$ is a casual sequence. If $y[0]=1$ and $y[1]=1/2$, then $g[1]$ equals $0$ $1/2$ $1$ $3.2$ new gate2012-ee + – Andrijana3306 asked Mar 23, 2018 • recategorized Nov 20, 2019 by go_editor Andrijana3306 1.4k points answer comment Share See all 0 reply Please log in or register to add a comment.