0 votes 0 votes In the circuit shown below, the current through the inductor is $\dfrac{2}{1+j} A\\ $ $\dfrac{-1}{1+j} A\\$ $\dfrac{1}{1+j} A \\$ $0 A$ new gate2012-ee + – Andrijana3306 asked Mar 23, 2018 • edited Sep 22, 2020 by go_editor Andrijana3306 1.4k points answer comment Share See all 0 reply Please log in or register to add a comment.
