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$\displaystyle{}\int \frac{z^2-4}{z^2+4}\: dz$ evaluated anticlockwise around the circle $\mid z-i \mid=2$ ,  where $i=\sqrt{-1}$, is

  1. $-4\pi$
  2. $0$
  3. $2+\pi$
  4. $2+2i$
in Differential Equations by (1.5k points)
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