0 votes 0 votes $\displaystyle{}\int \frac{z^2-4}{z^2+4}\: dz$ evaluated anticlockwise around the circle $\mid z-i \mid=2$ , where $i=\sqrt{-1}$, is $-4\pi$ $0$ $2+\pi$ $2+2i$ Complex Variables gate2013-ee complex-variables cauchys-integral-theorem + – piyag476 asked Feb 11, 2017 recategorized Mar 7, 2021 by Lakshman Bhaiya piyag476 1.5k points answer comment Share See all 0 reply Please log in or register to add a comment.