GO Electrical
0 votes

A dielectric slab with $500$ $mm$ $×$ $500$ $mm$ cross-section is $0.4$ $m$ long. The slab is subjected to a uniform electric field of $E=6a_x+8a_y$ $KV/mm$. The relative permittivity of the dielectric material is equal to $2$. The value of constant $\varepsilon _0$  is $8.85*10^{-12} F/M$ . The energy stored in the dielectric in Joules is

  1. $8.85*10^{-11}$
  2. $8.85*10^{-15}$
  3. $88.5$
  4. $885$
in Electromagnetic Fields by (1.5k points)
recategorized by

Please log in or register to answer this question.

Welcome to GATE Overflow, Electrical, where you can ask questions and receive answers from other members of the community.

847 questions
37 answers
26,032 users