0 votes 0 votes A voltage $1000 \sin \omega t$ Volts is applied across $YZ$. Assuming ideal diodes, the voltage measured across $WX$ in Volts is $\sin \omega t$ $(\sin \omega t + \sin \omega t ) / 2$ $(\sin \omega t - \sin \omega t ) / 2$ $0$ for all $t$ Electric Circuits gate2013-ee closed-loop diode + – piyag476 asked Feb 11, 2017 edited Nov 21, 2019 by go_editor piyag476 1.5k points answer comment Share See all 0 reply Please log in or register to add a comment.