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A strain gauge forms one arm of the bridge shown in the figure below and has a nominal resistance
without any load as $R_s$ = $300$ . Other bridge resistances are $R_1$ = $R_2$ = $R_3$ = $300$ . The maximum
permissible current through the strain gauge is $20$ $mA$. During certain measurement when the
bridge is excited by maximum permissible voltage and the strain gauge resistance is increased by
$1$% over the nominal value, the output voltage $V_0$ in $mV$ is

  1. $56.02$
  2. $40.83$
  3. $29.85$
  4. $10.02$
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1 Answer

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Voltage, Vin = (300+300)*20m

                      = 12v

Now, V 0 =  6-((300/603)*12)

                = 0.03v.   I.e., 30mV

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