0 votes 0 votes Integration of the complex function $f(z)=\dfrac{z^2}{z^2-1}$ , in the counterclockwise direction, around $\mid z-1 \mid = 1$, is $-\pi i$ $0$ $\pi i$ $2 \pi i$ Complex Variables gate2014-ee-3 complex-variables complex-functions cauchys-integral-theorem + – makhdoom ghaya asked Feb 11, 2017 • recategorized Mar 8, 2021 by Lakshman Bhaiya makhdoom ghaya 9.4k points answer comment Share See all 0 reply Please log in or register to add a comment.