The voltage across the capacitor, as shown in the figure, is expressed as
$V_c(t)=A_1\sin(\omega _1t-\theta _1)+A_2 \sin(\omega _2t-\theta _2)$
The values of $A_1 $and $A_2$ respectively, are
- $2.0$ and $1.98$
- $2.0$ and $4.20$
- $2.5$ and $3.50$
- $5.0$ and $6.40$