The switch SW shown in the circuit is kept at position $'1'$ for a long duration. At $t = 0+$, the switch is moved to position $'2'$. Assuming $\mid V_o2\mid > \mid V_o1\mid$, the voltage $v_c$(t) across the capacitor is
1. $V_c (t)=-V_{o2}(1-e^{-t/2RC})-V_{o1}$
2. $V_c (t)=V_{o2}(1-e^{-t/2RC})+V_{o1}$
3. $V_c (t)=-$($V_{o2}$+$V_{o1}$)$(1-e^{-t/2RC})-V_{o1}$
4. $V_c (t)=$($V_{o2}$+$V_{o1}$)$(1-e^{-t/2RC})+V_{o1}$