The switch SW shown in the circuit is kept at position $'1'$ for a long duration. At $t$ = $0+$, the switchis moved to position $'2'$. Assuming |$V_o2|$ > |$V_o1$|, the voltage $v_c$(t) across the capacitor is
1. $V_c (t)=-V_{o2}(1-e^{-t/2RC})-V_{o1}$
2. $V_c (t)=V_{o2}(1-e^{-t/2RC})+V_{o1}$
3. $V_c (t)=-$($V_{o2}$+$V_{o1}$)$(1-e^{-t/2RC})-V_{o1}$
4. $V_c (t)=$($V_{o2}$+$V_{o1}$)$(1-e^{-t/2RC})+V_{o1}$